In this blog post, we will see, how to write a C Program to Print Even Numbers from 1 to N using a while and for a loop. We will also see how we can print even numbers from 1 to N without using a branching statement ( if-else statement).
C Program to Print Even Numbers from 1 to 100 using While Loop:
Below mentioned program is used to print even numbers from 1 to N using the while loop. The value of N is asked by users with the help of a scanf (input) function.
#include<stdio.h>
int main()
{
int i = 2, number;
printf("\n Please Enter the Maximum Limit Value : ");
scanf("%d", &number);
printf("\n Even Numbers between 1 and %d are : \n", number);
while(i <= number)
{
printf(" %d\t", i);
i = i+2;
}
return 0;
}
Output:
Please Enter the Maximum Limit Value: 10
Even Numbers between 1 and 10 are :
2 4 6 8 10
C Program to Print Even Numbers from 1 to 100 using for Loop:
Below mentioned program is used to print even numbers from 1 to N using the for a loop. The value of N is asked by users with the help of a scanf (input) function.
#include<stdio.h>
int main()
{
int i, number;
printf("Please Enter the Maximum Limit Value : ");
scanf("%d", &number);
printf("Even Numbers between 1 and %d are : \n", number);
for(i = 1; i <= number; i++)
{
if ( i % 2 == 0 )
{
printf(" %d\t", i);
}
}
return 0;
}
Output:
Please Enter the Maximum Limit Value: 10
Even Numbers between 1 and 10 are :
2 4 6 8 10
C Program to Print Even Numbers from 1 to N without If Statement
#include<stdio.h>
int main()
{
int i, number;
printf("\n Please Enter the Maximum Limit Value : ");
scanf("%d", &number);
printf("\n Even Numbers between 1 and %d are : \n", number);
for(i = 2; i <= number; i= i+2)
{
printf(" %d\t", i);
}
return 0;
}
C Program to Print Even Numbers in a Given Range
Below mentioned C program allows the user to enter Minimum and maximum value. After that like the above-mentioned program, this C program will print even numbers in a given range.
#include<stdio.h>
int main()
{
int i, min, max;
printf("\n Please Enter the min Limit Value : ");
scanf("%d", &min);
printf("\n Please Enter the max Limit Values : ");
scanf("%d", &max);
if ( min % 2 != 0 )
{
min++;
}
printf("\n Even Numbers between %d and %d are : \n", min, max);
for(i = min; i <= max; i= i+2)
{
printf(" %d\t", i);
}
return 0;
}
Output:
Please Enter the min Limit Value: 5
Please Enter the max Limit Values: 10
Even Numbers between 6 and 10 are :
6 8 10